xx, yy = np.meshgrid(
np.arange(*range_features[feature_names[0]], plot_step),
np.arange(*range_features[feature_names[1]], plot_step),
)
Hey in this part of the plotting class what is the meaning of
*range_features[feature_names[0]
in
np.arange(*range_features[feature_names[0]], plot_step)
I understand that range_features is a dictionary, I am confused because I pointers aren’t allowed in python.
Hi Harshit_Sati,
In Python, the ‘*’ is used when you want to pass arguments contained in a list or a tuple to a function.
foo(*args) means you pass several arguments contained in a list or a tuple to the function foo().
Here range features is a dictionary indeed:
but the values of that dictionary are the range of culmen length and depth as tuples.
feature_names is the list of the keys of range_features. So =>
range_features[feature_names[0]] == range_features["Culmen Length (mm)"] == (31.1, 60.6)
in the function plot_step = 0.02 so =>
np.arange(*range_features[feature_names[0]], plot_step) == np.arange(*(31.1, 60.6), 0.02) == np.arange(31.1, 60.6, 0.02)
I hope I helped you to understand the code.
If you have any other question do not hesitate.
A nice tutorial for the use of *args and **kwargs in Python: here
yes thank you, that cleared all my doubts, I assumed it to be related to pointers 
, also it seems like the question was in a wrong thread
